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Question Number 83899 by john santu last updated on 07/Mar/20

Defined a function f(x) such   that f(1−x)+2f(x)= nx   for m ,n > 1 , the value of   ∫ _1 ^( m) (2n+6f((m/x))) dx is ...

Definedafunctionf(x)such thatf(1x)+2f(x)=nx form,n>1,thevalueof m1(2n+6f(mx))dxis...

Commented byjohn santu last updated on 07/Mar/20

replace 1−x by x in eq 1  f(x) + 2f(1−x) =n(1−x) (eq 2)  ⇒ 4f(x)+2f(1−x)=2nx  ⇒f(x)+2f(1−x) =n−nx  substract (1)by (2)  3f(x)= 3nx−n ⇒ f(x)=nx−(n/3)  f((m/x)) = ((nm)/x)−(n/3)  ∫ _1 ^( m)  (2n+6(((nm)/x)−(n/3)))dx =  ∫ _1 ^( m)  (2n+((6mn)/x)−2n) dx = m ln (m)^(6n)

replace1xbyxineq1 f(x)+2f(1x)=n(1x)(eq2) 4f(x)+2f(1x)=2nx f(x)+2f(1x)=nnx substract(1)by(2) 3f(x)=3nxnf(x)=nxn3 f(mx)=nmxn3 m1(2n+6(nmxn3))dx= m1(2n+6mnx2n)dx=mln(m)6n

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