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Question Number 8390 by tawakalitu last updated on 09/Oct/16

Answered by fernandodantas1996 last updated on 12/Oct/16

     i) F^→ +P^→  = 6i + 4j − k ⇒   ⇒ ∥F^→ +P^→ ∥=(√(6^2 +4^2 +(−1)^2 ))=(√(36+16+1))=(√(53))    ii) ((6i + 4j − k)/(√(53))) is the unit force

$$ \\ $$$$\: \\ $$$$\left.\mathrm{i}\right)\:\overset{\rightarrow} {\mathrm{F}}+\overset{\rightarrow} {\mathrm{P}}\:=\:\mathrm{6i}\:+\:\mathrm{4j}\:−\:\mathrm{k}\:\Rightarrow\: \\ $$$$\Rightarrow\:\parallel\overset{\rightarrow} {\mathrm{F}}+\overset{\rightarrow} {\mathrm{P}}\parallel=\sqrt{\mathrm{6}^{\mathrm{2}} +\mathrm{4}^{\mathrm{2}} +\left(−\mathrm{1}\right)^{\mathrm{2}} }=\sqrt{\mathrm{36}+\mathrm{16}+\mathrm{1}}=\sqrt{\mathrm{53}} \\ $$$$ \\ $$$$\left.\mathrm{ii}\right)\:\frac{\mathrm{6i}\:+\:\mathrm{4j}\:−\:\mathrm{k}}{\sqrt{\mathrm{53}}}\:\mathrm{is}\:\mathrm{the}\:\mathrm{unit}\:\mathrm{force} \\ $$

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