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Question Number 83943 by jagoll last updated on 08/Mar/20

lim_(x→0)  ((sec 6x−cos 2x)/(2x tan 5x))

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{sec}\:\mathrm{6x}−\mathrm{cos}\:\mathrm{2x}}{\mathrm{2x}\:\mathrm{tan}\:\mathrm{5x}} \\ $$$$ \\ $$

Answered by jagoll last updated on 08/Mar/20

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