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Question Number 84126 by Roland Mbunwe last updated on 09/Mar/20
∫5−x1+(x−4)dx
Answered by MJS last updated on 09/Mar/20
−∫x−51+x−4dx=∫(1−x−4)dx==x−23(x−4)32+C
Commented by MJS last updated on 09/Mar/20
−x−51+x−4×1−x−41−x−4=−(x−5)(1−x−4)5−x==1−x−4
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