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Question Number 84263 by Rio Michael last updated on 10/Mar/20
Usingtheapproximationh(dydx)n≈yn+1−ynandthatdydx=1,y=2whenx=0.then,y1=[A]h−2[B]h+2[C]h−1[D]h+1
Answered by mind is power last updated on 11/Mar/20
h(dydx)0≈y1−y0y1≈y0+h(dydx)0=2+1.h=h+2
Commented by Rio Michael last updated on 11/Mar/20
thanks
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