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Question Number 84335 by ajfour last updated on 11/Mar/20

Commented by ajfour last updated on 11/Mar/20

$$min(p+q+r)=f(a,b,c).Findf.$$

Commented by mr W last updated on 12/Mar/20

$$\mathrm{\Delta }=areaofABC=\frac{\sqrt{(a+b+c)(-a+b+c)(a-b+c)(a+b-c)}}{4}$$$$min(p+q+r)=3R=\frac{3abc}{4\mathrm{\Delta }}$$$$=\frac{3abc}{\sqrt{(a+b+c)(-a+b+c)(a-b+c)(a+b-c)}}$$

Commented by ajfour last updated on 12/Mar/20

$$doesthatmean,$$$$p+q+risminimumwhen$$$$p=q=r=R,Sir?$$

Commented by mr W last updated on 12/Mar/20

$$yes.duetosymmetry.$$

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