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Question Number 84404 by Wepa last updated on 12/Mar/20

$$({\mathrm{x}}^2-2)({\mathrm{x}}^2-4)({\mathrm{x}}^2-6)...({\mathrm{x}}^2-2020)=1$$$$\mathrm{x}=?$$

Commented by TANMAY PANACEA last updated on 12/Mar/20

$$excllentproblem...needmoretimetothink$$

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