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Question Number 84628 by mr W last updated on 14/Mar/20

Commented by mr W last updated on 14/Mar/20

$T h e d i s t a n c e b e t w e e n A a n d B i s d .$ $T w o p r o j e c t i l e s a r e s h o t a t t h e s a m e$ $t i m e a s s h o w n .$ $A f t e r w h i c h t i m e a r e t h e p r o j e c t i l e s$ $c l o s e s t t o e a c h o t h e r ? F i n d t h i s$ $s m a l l e s t d i s t a n c e b e t w e e n t h e m .$
	Answered by ajfour last updated on 14/Mar/20

	Commented by ajfour last updated on 14/Mar/20

	$v = \sqrt{u_{1}^{2} + u_{2}^{2} + 2 u_{1} u_{2} \cos (θ_{1} + θ_{2})}$ $\tan (θ_{1} + α) = \frac{u_{2} \sin (θ_{1} + θ_{2})}{u_{1} + u_{2} \cos (θ_{1} + θ_{2})}$ $t_{s} = \frac{d \cos α}{v}, s = d \sin α .$
	Commented by mr W last updated on 14/Mar/20

	$p e r f e c t s i r!$
	Commented by mr W last updated on 14/Mar/20

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