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Question Number 84728 by mr W last updated on 15/Mar/20

$$y=x\left[x\left[x\right]\right]withx\in R^{+}$$$$findtherangeoffunction$$$$andsolvex\left[x\left[x\right]\right]=150.$$

Commented by MJS last updated on 16/Mar/20

Commented by MJS last updated on 16/Mar/20

$$\mathrm{this}\mathrm{is}\mathrm{my}\mathrm{work}\mathrm{to}\mathrm{an}\mathrm{earlier}\mathrm{question}.\mathrm{I}\mathrm{never}$$$$\mathrm{posted}\mathrm{it}\mathrm{before}$$

Commented by mr W last updated on 16/Mar/20

$$thankyousir!{that}^{\prime }sperfect.$$

Commented by MJS last updated on 16/Mar/20

$$\mathrm{I}\mathrm{started}\mathrm{trying}\mathrm{the}\mathrm{next}\mathrm{stage}$$$$x\left[x\left[x\left[x\right]\right]\right]$$$$\mathrm{but}{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{getting}\mathrm{very}\mathrm{complex}$$

Commented by mr W last updated on 16/Mar/20

$${that}^{\prime }struesir!$$

Commented by M±th+et£s last updated on 16/Mar/20

$$ithinkthereisatypo$$$$ifi=2k=110⩽n⩽15$$

Commented by M±th+et£s last updated on 16/Mar/20

$$and$$$$27⩽n⩽30$$

Commented by MJS last updated on 16/Mar/20

$$\mathrm{you}\mathrm{are}\mathrm{wrong}\mathrm{because}\mathrm{also}$$$$q=i^2+k$$$$\mathrm{and}$$$$\frac{k}{i}⩽f<\frac{k+1}{i}$$$$\mathrm{try}\mathrm{it},\mathrm{you}\mathrm{cannot}\mathrm{get}10,11,12\mathrm{as}\mathrm{solution}$$$${\mathrm{it}}^{\prime }\mathrm{s}\mathrm{not}\mathrm{easy}\mathrm{to}\mathrm{understand}\mathrm{the}\mathrm{jumps}\mathrm{of}$$$$y=x\left[x\left[x\right]\right]$$

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