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Question Number 84904 by john santu last updated on 17/Mar/20

3^(2x^2 )  + 3^(x^2 +2x+5)  ≥ 10. 3^(4x+6)

32x2+3x2+2x+510.34x+6

Commented by john santu last updated on 17/Mar/20

let 3^x^2   = u & 3^(2x+3)  = v  ⇒ u^2 +9uv−10v^2  ≥ 0  ⇒ (u−v)(u+10v) ≥ 0   ⇒u ≥ v , 3^x^2   ≥ 3^(2x+3)   ⇒ x^2 −2x−3 ≥ 0   x ≤ −1 ∨ x ≥ 3

let3x2=u&32x+3=vu2+9uv10v20(uv)(u+10v)0uv,3x232x+3x22x30x1x3

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