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Question Number 84957 by john santu last updated on 17/Mar/20
∫(2−x2)3dx=
Commented by john santu last updated on 17/Mar/20
∫(8−3(4x2)+3(2x4)−x6)dx=∫(8−12x2+6x4−x6)dx=8x−4x3+65x5−17x7+c
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