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Question Number 8498 by Chantria last updated on 13/Oct/16

Commented by Rasheed Soomro last updated on 13/Oct/16

((2a^2 )/(3a+bc))×(√(1/(b+c)))×((18ab)/((3b)^2 −5c))  =((2a^2 )/(3a+bc))×(1/(√(b+c)))×((18ab)/(9b^2 −5c))  =((36a^3 b)/((3a+bc)(9b^2 −5c)(√(b+c))))

$$\frac{\mathrm{2a}^{\mathrm{2}} }{\mathrm{3a}+\mathrm{bc}}×\sqrt{\frac{\mathrm{1}}{\mathrm{b}+\mathrm{c}}}×\frac{\mathrm{18ab}}{\left(\mathrm{3b}\right)^{\mathrm{2}} −\mathrm{5c}} \\ $$$$=\frac{\mathrm{2a}^{\mathrm{2}} }{\mathrm{3a}+\mathrm{bc}}×\frac{\mathrm{1}}{\sqrt{\mathrm{b}+\mathrm{c}}}×\frac{\mathrm{18ab}}{\mathrm{9b}^{\mathrm{2}} −\mathrm{5c}} \\ $$$$=\frac{\mathrm{36a}^{\mathrm{3}} \mathrm{b}}{\left(\mathrm{3a}+\mathrm{bc}\right)\left(\mathrm{9b}^{\mathrm{2}} −\mathrm{5c}\right)\sqrt{\mathrm{b}+\mathrm{c}}} \\ $$

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