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Question Number 85248 by jagoll last updated on 20/Mar/20
findminimumy=2∣x−3∣+∣4x+2∣
Commented by mr W last updated on 20/Mar/20
x−3=0⇒x=34x+2=0⇒x=−12f(3)=∣12+2∣=14f(−12)=2∣−12−3∣=7ymin=min(f(3),f(−12))=7
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