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Question Number 85319 by sahnaz last updated on 20/Mar/20

$$\int \frac{2+\mathrm{u}}{-{\mathrm{u}}^2-\mathrm{u}}\mathrm{du}$$

Answered by MJS last updated on 20/Mar/20

$$\int \frac{2+u}{-u^2-u}du=-\int \frac{u+2}{u(u+1)}du=$$$$=\int \frac{du}{u+1}-2\int \frac{du}{u}=\ln \mid u+1\mid -2\ln \mid u\mid +C$$

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