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Question Number 85625 by jagoll last updated on 23/Mar/20
limx→0xn−(sinx)n(sinx)n+2
Answered by john santu last updated on 23/Mar/20
byMaclaurinseriessinx=x−x33!+...sinnx=xn(1−x23!+...)nletL=limx→0xn−xn(1−x26+...)nxn+2(1−x26+...)n+2L=limx→0nxn+26−o(xn+4)xn+2−o(xn+6)L=n6
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