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Question Number 8571 by tawakalitu last updated on 16/Oct/16

Commented by sandy_suhendra last updated on 16/Oct/16

Is the potensial of supply 1.0 volt?

$$\mathrm{Is}\:\mathrm{the}\:\mathrm{potensial}\:\mathrm{of}\:\mathrm{supply}\:\mathrm{1}.\mathrm{0}\:\mathrm{volt}? \\ $$

Commented by tawakalitu last updated on 16/Oct/16

yes sir.

$$\mathrm{yes}\:\mathrm{sir}. \\ $$

Answered by ridwan balatif last updated on 17/Oct/16

Answered by ridwan balatif last updated on 17/Oct/16

Commented by tawakalitu last updated on 17/Oct/16

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

Answered by sandy_suhendra last updated on 17/Oct/16

Commented by sandy_suhendra last updated on 17/Oct/16

if the voltmeter is disconnected, the circuit looks like above the potensial of supply=E=1 volt so ΔV_(AB) =E=1 volt=ΔV_(AC) +ΔV_(CB) ΔV_(AC) : ΔV_(CB) = R_1 :R_2 =500:1500=1:3 so ΔV_(CB) =(3/4)×1=(3/4) volt ΔV_(AC) =(1/4)×1=(1/4) volt (when the voltmeter is connected, I think it′s imposible if E=1 volt and the p.d. reads at the voltmeter is 1 volt too)

$$\mathrm{if}\:\mathrm{the}\:\mathrm{voltmeter}\:\mathrm{is}\:\mathrm{disconnected},\:\mathrm{the}\:\mathrm{circuit}\:\mathrm{looks}\:\mathrm{like}\:\mathrm{above} \\ $$$$\mathrm{the}\:\mathrm{potensial}\:\mathrm{of}\:\mathrm{supply}=\mathrm{E}=\mathrm{1}\:\mathrm{volt} \\ $$$$\mathrm{so}\:\:\Delta\mathrm{V}_{\mathrm{AB}} =\mathrm{E}=\mathrm{1}\:\mathrm{volt}=\Delta\mathrm{V}_{\mathrm{AC}} +\Delta\mathrm{V}_{\mathrm{CB}} \\ $$$$\Delta\mathrm{V}_{\mathrm{AC}} \::\:\Delta\mathrm{V}_{\mathrm{CB}} \:=\:\mathrm{R}_{\mathrm{1}} :\mathrm{R}_{\mathrm{2}} =\mathrm{500}:\mathrm{1500}=\mathrm{1}:\mathrm{3} \\ $$$$\mathrm{so}\:\Delta\mathrm{V}_{\mathrm{CB}} =\frac{\mathrm{3}}{\mathrm{4}}×\mathrm{1}=\frac{\mathrm{3}}{\mathrm{4}}\:\mathrm{volt} \\ $$$$\Delta\mathrm{V}_{\mathrm{AC}} =\frac{\mathrm{1}}{\mathrm{4}}×\mathrm{1}=\frac{\mathrm{1}}{\mathrm{4}}\:\mathrm{volt} \\ $$$$\left(\mathrm{when}\:\mathrm{the}\:\mathrm{voltmeter}\:\mathrm{is}\:\mathrm{connected},\:\mathrm{I}\:\mathrm{think}\right. \\ $$$$\mathrm{it}'\mathrm{s}\:\mathrm{imposible}\:\mathrm{if}\:\mathrm{E}=\mathrm{1}\:\mathrm{volt}\:\mathrm{and}\:\mathrm{the}\:\mathrm{p}.\mathrm{d}.\:\mathrm{reads}\:\mathrm{at} \\ $$$$\left.\mathrm{the}\:\mathrm{voltmeter}\:\mathrm{is}\:\mathrm{1}\:\mathrm{volt}\:\mathrm{too}\right) \\ $$

Commented by tawakalitu last updated on 17/Oct/16

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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