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Question Number 85789 by Rio Michael last updated on 24/Mar/20
∫(lnx)2dx=
Answered by sakeefhasan05@gmail.com last updated on 24/Mar/20
=(lnx)2.x−∫x.2(lnx).1xdx=x(lnx)2−2[(lnx).x−∫x.1xdx]=x(lnx)2−2x(lnx))+2x+C
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