Question and Answers Forum

All Questions      Topic List

Differential Equation Questions

Previous in All Question      Next in All Question      

Previous in Differential Equation      Next in Differential Equation      

Question Number 85834 by sahnaz last updated on 25/Mar/20

2y^′ −(x/y)=((xy)/(x^2 −1))

2yxy=xyx21

Answered by mind is power last updated on 27/Mar/20

⇔2y′y−x=((xy^2 )/(x^2 −1))  u=y^2 ⇒2y′y=u′  ⇒u′−x=((xu)/(x^2 −1))  ⇒xu−(x^2 −1)u′−x(x^2 −1)=0 easy now

2yyx=xy2x21u=y22yy=uux=xux21xu(x21)ux(x21)=0easynow

Terms of Service

Privacy Policy

Contact: info@tinkutara.com