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Question Number 85834 by sahnaz last updated on 25/Mar/20
2y′−xy=xyx2−1
Answered by mind is power last updated on 27/Mar/20
⇔2y′y−x=xy2x2−1u=y2⇒2y′y=u′⇒u′−x=xux2−1⇒xu−(x2−1)u′−x(x2−1)=0easynow
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