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Question Number 85835 by sahnaz last updated on 25/Mar/20

$$\mathrm{xydy}=({\mathrm{y}}^2+\mathrm{x})\mathrm{dx}$$

Answered by TANMAY PANACEA. last updated on 25/Mar/20

$$xydy-y^{2}dx=xdx$$$$y(xdy-ydx)=xdx$$$$\left(\frac{y}{x}\right)\left(\frac{xdy-ydx}{x^2}\right)=\frac{dx}{x^2}$$$$\left(\frac{y}{x}\right)d\left(\frac{y}{x}\right)=x^{-2}dx$$$$intregating$$$$\frac{{\left(\frac{y}{x}\right)}^2}{2}=\frac{-1}{x}+c$$

Commented by sahnaz last updated on 25/Mar/20

$$\mathrm{thank}\mathrm{you}\mathrm{dear}\mathrm{friend}$$

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