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Question Number 85859 by jagoll last updated on 25/Mar/20

$$\mathrm{Is}\mathrm{the}\mathrm{Var}(\mathrm{aX}+\mathrm{b})={\mathrm{a}}^2\mathrm{Var}\left(\mathrm{X}\right)+\mathrm{b}?$$

Answered by Joel578 last updated on 25/Mar/20

$$nope$$$$\mathrm{Assume}a\mathrm{and}b\mathrm{is}\mathrm{constant},\mathrm{then}$$$$\mathrm{var}\left(b\right)=E\left[b^2\right]-{\left\{E\left[b\right]\right\}}^2=b^2-b^2=0$$$$$$$$\mathrm{var}(aX+b)=\mathrm{var}\left(aX\right)+\mathrm{var}\left(b\right)=a^2\mathrm{var}\left(X\right)$$

Commented by jagoll last updated on 26/Mar/20

$$\mathrm{yes}\mathrm{sir}.\mathrm{agree}$$

Answered by jagoll last updated on 26/Mar/20

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