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Question Number 85875 by sakeefhasan05@gmail.com last updated on 25/Mar/20

∫((1/(7[1−(1/7)e^x ]))) dx

(17[117ex])dx

Answered by TANMAY PANACEA. last updated on 25/Mar/20

(1/7)∫((e^(−x) dx)/(e^(−x) −(1/7))) (multiply N_r and D_r  by e^(−x) )  t=e^(−x) −(1/7)→(dt/dx)=−e^(−x)   (1/7)∫((−dt)/t)=((−1)/7)lnt+c  ((−1)/7)ln(e^(−x) −(1/7))+c

17exdxex17(multiplyNrandDrbyex)t=ex17dtdx=ex17dtt=17lnt+c17ln(ex17)+c

Commented by sakeefhasan05@gmail.com last updated on 25/Mar/20

thank u very much

thankuverymuch

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