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Question Number 116779 by mathdave last updated on 06/Oct/20

$$solve$$$$x^x=2$$

Answered by Dwaipayan Shikari last updated on 06/Oct/20

$$xlogx=log\left(2\right)$$$${logxe}^{logx}=log\left(2\right)$$$$logx=W_0\left(log\left(2\right)\right)$$$$x=e^{W_0\left(log\left(2\right)\right)}=1.559610$$

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