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Question Number 86189 by oustmuchiya@gmail.com last updated on 27/Mar/20

$$Giventhat\mathbf{f}\left(\mathbf{x}\right)=\frac{2\mathbf{x}+7}{8}and\mathbf{g}\left(\mathbf{x}\right)=\frac{3\mathbf{x}-6}{6},find$$$$\left(\mathrm{a}\right)\mathbf{g}\left(6\right),\left(\mathrm{b}\right){\mathbf{f}}^{-1}\left(\mathbf{x}\right)\left(\mathrm{c}\right)\mathrm{the}\mathrm{value}\mathrm{of}\mathbf{x}if\mathbf{f}\left(\mathbf{x}\right)=\mathbf{g}\left(\mathbf{x}\right)$$

Answered by Kunal12588 last updated on 27/Mar/20

$$\left(a\right)g\left(6\right)=\frac{18-6}{6}=2$$$$\left(b\right)f^{-1}\left(x\right)=\frac{8x-7}{2}$$$$\left(c\right)12x+42=24x-48$$$$\Rightarrow 12x=90$$$$\Rightarrow x=\frac{15}{2}=7.5$$

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