let x^x^x^⋰ =2 x^2 =2 x=±(√2) then let x^x^x^⋰ =4 x^4 =4 x=±(4)^(1/4) =±(√2) so we had prove 2=4 right?


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Question Number 86298 by 21042009 last updated on 28/Mar/20

$l e t x^{x^{x^{\iddots}}} = 2$ $x^{2} = 2$ $x = \pm \sqrt{2}$ $t h e n l e t x^{x^{x^{\iddots}}} = 4$ $x^{4} = 4$ $x = \pm \sqrt[4]{4} = \pm \sqrt{2}$ $s o w e h a d p r o v e 2 = 4 r i g h t ?$
Commented by john santu last updated on 28/Mar/20

$h a h a h a . . n o$
Commented by 20092104 last updated on 28/Mar/20

$w h y$
Commented by Kunal12588 last updated on 28/Mar/20

$1^{0} = 1, 2^{0} = 1$ $1 \neq 2 (w h y ?) :)$
Commented by john santu last updated on 28/Mar/20

$10000000^{0} = e^{0}$ $10000000 = e$ $why ?$
Commented by 20092104 last updated on 29/Mar/20

$d o m a i n o f x^{x^{x^{\iddots}}} i s [\frac{1}{e^{e}}, e^{\frac{1}{e}}]$
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