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Question Number 86343 by jagoll last updated on 28/Mar/20

Dear mr w. i want   discuss for equation  find minimum and maximum value  of xy +2 with constraint  x^2 +y^(2 ) = 6.  my way (short cut)  ⇒ x^2  = y^2  = 3   { ((max = ((√3))^2 +2 = 5)),((min = −((√3))^2  +1 = −1)) :}  it correct?

Dearmrw.iwantdiscussforequationfindminimumandmaximumvalueofxy+2withconstraintx2+y2=6.myway(shortcut)x2=y2=3{max=(3)2+2=5min=(3)2+1=1itcorrect?

Commented by mr W last updated on 28/Mar/20

this is correct, because both in xy+2  and in x^2 +y^2 =6 there is the symmetry  for x and y, i.e. x and y are equally  valued.

thisiscorrect,becausebothinxy+2andinx2+y2=6thereisthesymmetryforxandy,i.e.xandyareequallyvalued.

Commented by jagoll last updated on 28/Mar/20

thank you very much mister

thankyouverymuchmister

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