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Question Number 86356 by MASANJAJ last updated on 28/Mar/20

Commented by MASANJAJ last updated on 28/Mar/20

$p l e a s e h e l p m e t o f i n d i n q u a l i t i e s o f$ $t h i s q u e s t i o n$
	Answered by MJS last updated on 28/Mar/20

	$40 x + 60 y = \max$ $x + y = 10 \Rightarrow y = 10 - x$ $x ⩾ 2 \land y ⩾ 2$ $x ⩾ 2 \land 10 - x ⩾ 2 \Leftrightarrow 2 ⩽ x ⩽ 8$ $40 x + 60 (10 - x) = 600 - 20 x$ $\Rightarrow maximum at x = 2 \land y = 8$
	Commented by MASANJAJ last updated on 28/Mar/20

	$h o w a b o u t 150 s h a n d 200 s h$
	Commented by MJS last updated on 28/Mar/20

	$we do not need this info$ ${there}^{'} s no limitation how much money she$ $can spend$
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