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Question Number 86472 by Chi Mes Try last updated on 28/Mar/20

Answered by TANMAY PANACEA. last updated on 28/Mar/20

∫_(−1) ^1 xdx−∫_(−1) ^1 [x]dx ∫_(−1) ^1 xdx−{∫_(−1) ^0 [x]dx+∫_0 ^1 [x]dx} =∣(x^2 /2)∣_(−1) ^1 −{∫_(−1) ^0 (−1)dx+∫_0 ^1 0×dx} =0−{−∣x∣_(−1) ^0 +0} =∣x∣_(−1) ^0 =(0+1)=1

∫−11xdx−∫−11[x]dx∫−11xdx−{∫−10[x]dx+∫01[x]dx}=∣x22∣−11−{∫−10(−1)dx+∫010×dx}=0−{−∣x∣−10+0}=∣x∣−10=(0+1)=1

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