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Question Number 86479 by Rio Michael last updated on 28/Mar/20

a ball is droped from a height 20 m. Given that it  rebounce with a velocity of (3/4) that which it hit the ground  find the time interval between the first and second rebounce.

aballisdropedfromaheight20m.Giventhatitrebouncewithavelocityof34thatwhichithitthegroundfindthetimeintervalbetweenthefirstandsecondrebounce.

Answered by mr W last updated on 29/Mar/20

the height after a rebounce is ((3/4))^2  of  the height before the rebounce.  h_0 =20 m  h_1 =((3/4))^2 20=11.25 m  between the first and second rebounce  the ball reaches a height of 11.25m  and falls down again. the time needed  is t_1 =2(√((2h_1 )/g))=2(√((2×11.25)/(10)))=3 sec

theheightafterarebounceis(34)2oftheheightbeforetherebounce.h0=20mh1=(34)220=11.25mbetweenthefirstandsecondrebouncetheballreachesaheightof11.25mandfallsdownagain.thetimeneededist1=22h1g=22×11.2510=3sec

Commented by Rio Michael last updated on 29/Mar/20

thanks sir

thankssir

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