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Question Number 86552 by M±th+et£s last updated on 29/Mar/20

proe that  f(x)=x+[x]   increase in R

proethatf(x)=x+[x]increaseinR

Commented by mathmax by abdo last updated on 29/Mar/20

f^′ (x)=1      because [x] ∈Z ⇒f is increasing at R

f(x)=1because[x]ZfisincreasingatR

Commented by M±th+et£s last updated on 29/Mar/20

thank you sir

thankyousir

Commented by mathmax by abdo last updated on 30/Mar/20

you are welcome.

youarewelcome.

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