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Question Number 86655 by jagoll last updated on 30/Mar/20
limx→−1+π−arccosxx+1
Answered by john santu last updated on 30/Mar/20
L′hopitalrulelimx→−1+−12(arccosx)−12(−11−x2)12x+1limx→−1+1arccosx×1+x1−x2limx→−1+1arccosx×11−x1π×12=12π
Commented by jagoll last updated on 30/Mar/20
thankyou
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