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Question Number 86663 by ram roop sharma last updated on 30/Mar/20

$$\mathrm{The}\mathrm{matrix}A\mathrm{satisfying}\mathrm{the}\mathrm{equation}$$$$\left[\begin{array}{cc}1& 3\\ 0& 1\end{array}\right]A=\left[\begin{array}{cc}1& 1\\ 0& -1\end{array}\right]\mathrm{is}$$

Commented by Prithwish Sen 1 last updated on 30/Mar/20

$$\left[\begin{array}{c}14\\ 0-1\end{array}\right]$$

Answered by Kunal12588 last updated on 30/Mar/20

$$A={\left[\begin{array}{cc}1& 3\\ 0& 1\end{array}\right]}^{-1}\left[\begin{array}{cc}1& 1\\ 0& -1\end{array}\right]$$$$A=\left[\begin{array}{cc}1& -3\\ 0& 1\end{array}\right]\left[\begin{array}{cc}1& 1\\ 0& -1\end{array}\right]$$$$A=\left[\begin{array}{cc}1& 4\\ 0& -1\end{array}\right]$$

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