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Question Number 86671 by M±th+et£s last updated on 30/Mar/20
∫sin(x)arcsin(x)
Answered by Rio Michael last updated on 30/Mar/20
letmegiveatry.∫sin(x)arcsin(x)dxusingthetaylorseriesexpansionforsin(x)arcsin(x)centredat0sin(x)arcsin(x)=x2+x618+x830+2669x10113400+601x1234020+...⇒∫sin(x)arcsin(x)dx=∫(x2+x618+x830+2669x10113400+601x1234020+...)dx=x33+x7126+x9270+2669x111247400+601x13442260+...+kistillpersonallythinkthisproblemwillbecoolifwehadboundaryconditionslike∫01sin(x)arcsin(x)dx.
Commented by M±th+et£s last updated on 30/Mar/20
thankyousir
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