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Question Number 86937 by TawaTawa1 last updated on 01/Apr/20

Commented by john santu last updated on 01/Apr/20

$$\mathrm{radius}\mathrm{smaller}\mathrm{circle}=\frac{8}{15}$$$$\mathrm{miss}\mathrm{tawa}$$

Commented by john santu last updated on 01/Apr/20

Commented by john santu last updated on 01/Apr/20

$$\cos \theta =\cos \theta$$$$\frac{2\mathrm{R}}{3\mathrm{x}\sqrt{5}}=\frac{\mathrm{x}}{4\sqrt{5}}\Rightarrow \mathrm{R}=\frac{{3\mathrm{x}}^2}{8}...\left(\mathrm{i}\right)$$$${12}^2={\left(4\sqrt{5}\right)}^2+{\left(3\mathrm{x}\sqrt{5}\right)}^2$$$$144-80={45\mathrm{x}}^2\Rightarrow {\mathrm{x}}^2=\frac{64}{45}...\left(\mathrm{ii}\right)$$$$\Rightarrow \mathrm{R}=\frac{3}{8}\times \frac{64}{45}=\frac{8}{15}$$

Commented by TawaTawa1 last updated on 01/Apr/20

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir},\mathrm{i}\mathrm{appreciate}\mathrm{your}\mathrm{time}$$

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