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Question Number 86998 by M±th+et£s last updated on 01/Apr/20
∫6exe2x−1dx
Answered by TANMAY PANACEA. last updated on 01/Apr/20
∫6d(ex)(ex+1)(ex−1)6∫dt(t+1)(t−1)3∫(t+1)−(t−1)(t+1)(t−1dt3∫dtt−1−3∫dtt+13ln(t−1t+1)+c3ln(ex−1ex+1)+c
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