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Question Number 86998 by M±th+et£s last updated on 01/Apr/20

∫((6e^x )/(e^(2x) −1)) dx

6exe2x1dx

Answered by TANMAY PANACEA. last updated on 01/Apr/20

∫((6d(e^x ))/((e^x +1)(e^x −1)))  6∫(dt/((t+1)(t−1)))  3∫(((t+1)−(t−1))/((t+1)(t−1))dt  3∫(dt/(t−1))−3∫(dt/(t+1))  3ln(((t−1)/(t+1)))+c  3ln(((e^x −1)/(e^x +1)))+c

6d(ex)(ex+1)(ex1)6dt(t+1)(t1)3(t+1)(t1)(t+1)(t1dt3dtt13dtt+13ln(t1t+1)+c3ln(ex1ex+1)+c

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