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Question Number 87133 by jagoll last updated on 03/Apr/20

Commented by jagoll last updated on 03/Apr/20

$$\mathrm{dear}\mathrm{miss}\mathrm{tawa}.$$$$\mathrm{\angle }\mathrm{MEA}={45}^{\mathrm{o}},\mathrm{\angle }\mathrm{CAB}={19}^{\mathrm{o}}$$$$\mathrm{find}\mathrm{\angle }\mathrm{CPB}=?$$

Commented by arcana last updated on 03/Apr/20

$$77°=m\mathrm{\angle }EPD=m\mathrm{\angle }CPB$$

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