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Question Number 87376 by naka3546 last updated on 04/Apr/20

Answered by john santu last updated on 04/Apr/20

$${\mathrm{A}}^3=\left(\begin{array}{c}3-2\\ 3-4\end{array}\right)-\left(\begin{array}{c}2-1\\ 11\end{array}\right)$$$${\mathrm{A}}^3=\left(\begin{array}{c}1-1\\ 2-3\end{array}\right)$$$$\det \left(\mathrm{A}\right)=\sqrt[3]{-3+2}=-1$$$$\det \left({3\mathrm{A}}^{-1}\right)=\frac{9}{\det \left(\mathrm{A}\right)}=-9$$

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