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Question Number 87790 by mathocean1 last updated on 06/Apr/20

$$\mathrm{How}\mathrm{many}\mathrm{handshakes}\mathrm{are}\mathrm{exchanged}$$$$\mathrm{betwen}27\mathrm{boys}?$$

Answered by TANMAY PANACEA. last updated on 06/Apr/20

$$27C_2$$$$=\frac{27!}{2!25!}=\frac{27\times 26}{2}=351$$

Answered by Serlea last updated on 06/Apr/20

$$\mathrm{for}\mathrm{n}⩾2\mathrm{it}\mathrm{exist}$$$${\mathrm{a}}_2=1$$$${\mathrm{a}}_3=2+1$$$${\mathrm{a}}_4=3+2+1$$$${\mathrm{a}}_5=4+3+2+1$$$${\mathrm{a}}_{27}=26+25+24+23+....+1$$$$=\frac{26(26+1)}{2}=13\times 27=351$$

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