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Question Number 87988 by M±th+et£s last updated on 07/Apr/20

solve the PDE  1−Z=px+py−q(√(pq))  2−Z=px+qy+sin(p+q)  3−p(1+q^2 )=q(Z−a)  4−Z=xyp^2

solvethePDE1Z=px+pyqpq2Z=px+qy+sin(p+q)3p(1+q2)=q(Za)4Z=xyp2

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