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Question Number 88179 by ubaydulla last updated on 08/Apr/20

$$z=x^2/y^{3}dz=?$$

Answered by TANMAY PANACEA. last updated on 08/Apr/20

$$dz={\left(\frac{\partial z}{\partial x}\right)}_{y}dx+{\left(\frac{\partial z}{\partial y}\right)}_{x}dy$$$$=\frac{1}{y^3}\times 2xdx+x^2\times (-3)y^{-4}dy$$$$dz=\frac{2xdx}{y^3}-\frac{3x^{2}dy}{y^4}$$

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