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Question Number 88300 by byaw last updated on 09/Apr/20

A circle touches the four sides  of quadrilateral ABCD. Show/prove  that AB+CD=BC+DA.  Please help.

$${A}\:{circle}\:{touches}\:{the}\:{four}\:{sides} \\ $$$${of}\:{quadrilateral}\:{ABCD}.\:\mathrm{Show}/\mathrm{prove} \\ $$$$\mathrm{that}\:\mathrm{A}{B}+{CD}={BC}+{DA}. \\ $$$$\mathrm{Please}\:\mathrm{help}. \\ $$

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