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Question Number 88417 by M±th+et£s last updated on 10/Apr/20

e^(−z)  _1 f_1 (a;b;z)=((Γ(b))/(Γ(b−a))) G_(1,2) ^(1,1) (z∣_(0,1−b) ^(a−b+1) )

ez1f1(a;b;z)=Γ(b)Γ(ba)G1,21,1(z0,1bab+1)

Commented by M±th+et£s last updated on 10/Apr/20

G is meijer function  f is hypergeometric function

Gismeijerfunctionfishypergeometricfunction

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