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Question Number 88439 by otchereabdullai@gmail.com last updated on 10/Apr/20

$$\mathrm{kofi}\mathrm{have}\mathrm{three}\mathrm{books}\mathrm{on}\mathrm{his}\mathrm{desk},\mathrm{they}$$$$\mathrm{are}\mathrm{mathematics},\mathrm{biology}\mathrm{and}\mathrm{physics}.$$$$\mathrm{Ama}\mathrm{also}\mathrm{have}\mathrm{three}\mathrm{books}\mathrm{on}$$$$\mathrm{her}\mathrm{desk}\mathrm{namely}\mathrm{physics},\mathrm{mathematics}$$$$\mathrm{and}\mathrm{chemistry}.\mathrm{A}\mathrm{thief}\mathrm{picked}\mathrm{one}\mathrm{book}$$$$\mathrm{from}\mathrm{each}\mathrm{of}\mathrm{their}\mathrm{desk}.\mathrm{what}\mathrm{is}\mathrm{the}$$$$\mathrm{probability}\mathrm{of}\mathrm{picking}\mathrm{mathematics}$$$$\mathrm{book}$$

Commented by mr W last updated on 10/Apr/20

$$way1:$$$$probabilityofpickingMfromM,B$$$$andPbyKofiis{p}_1=\frac{1}{3}.$$$$probabilityofpickingMfromP,M$$$$andCbyAmais{p}_2=\frac{1}{3}.$$$$probabilityofpickingMbothbyKofi$$$$andbyAmaisthen$$$$p=p_1\times p_2=\frac{1}{3}\times \frac{1}{3}=\frac{1}{9}$$$$$$$$way2:$$$$topickabookbyKofithereare3$$$$possibilitiesandtopickabookby$$$$Amathereare3possibilities,totally$$$$thereare3\times 3=9possibilities.$$$$topicktheMbookbothbyKofiand$$$$byAmathereis1possibility.$$$$theprobabilityisthen$$$$\Rightarrow p=\frac{1}{9}$$

Commented by otchereabdullai@gmail.com last updated on 10/Apr/20

$$\mathrm{Prof}\mathrm{W}\mathrm{i}\mathrm{dont}\mathrm{know}\mathrm{the}\mathrm{word}\mathrm{to}$$$$\mathrm{discribe}\mathrm{you}!\mathrm{all}\mathrm{what}\mathrm{i}\mathrm{will}\mathrm{say}\mathrm{is}\mathrm{God}$$$$\mathrm{bless}\mathrm{you}\mathrm{and}\mathrm{protect}\mathrm{you}\mathrm{for}\mathrm{us}.$$$$\mathrm{because}\mathrm{you}\mathrm{are}\mathrm{so}\mathrm{special}.\mathrm{i}\mathrm{alway}$$$$\mathrm{pray}\mathrm{for}\mathrm{long}\mathrm{life}\mathrm{for}\mathrm{you}$$$$$$

Commented by mr W last updated on 10/Apr/20

$$thankyousir!$$

Commented by Ar Brandon last updated on 10/Apr/20

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