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Question Number 88487 by I want to learn more last updated on 11/Apr/20

Commented by I want to learn more last updated on 11/Apr/20

Please help.

Pleasehelp.

Commented by jagoll last updated on 11/Apr/20

(3+r)^2  = (3−r)^2 +(5−r)^2   (3+r)^2 −(3−r)^2 =(5−r)^2   (6)(2r) = r^2 −10r+25  r^2 −22r+25 = 0  r = ((22 − (√(22^2 −100)))/2) = ((22−19.6)/2)  r ≈ 1.2 cm

(3+r)2=(3r)2+(5r)2(3+r)2(3r)2=(5r)2(6)(2r)=r210r+25r222r+25=0r=222221002=2219.62r1.2cm

Commented by $@ty@m123 last updated on 11/Apr/20

Nice....

Nice....

Commented by I want to learn more last updated on 11/Apr/20

Oh yes. I get it now. I apprectiate.

Ohyes.Igetitnow.Iapprectiate.

Commented by I want to learn more last updated on 11/Apr/20

Wow great.  Sorry to border you sir, am weak in geometry, can you please help me  join how you derive the equation?.

Wowgreat.Sorrytoborderyousir,amweakingeometry,canyoupleasehelpmejoinhowyouderivetheequation?.

Commented by $@ty@m123 last updated on 11/Apr/20

Commented by $@ty@m123 last updated on 11/Apr/20

Apply Pythagoras theorem in right  angled triangle ABC.

ApplyPythagorastheoreminrightangledtriangleABC.

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