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Question Number 8859 by lepan last updated on 02/Nov/16

If ((tan(α+β−γ))/(tan(a−β+γ)))=((tanγ)/(tanβ)) then show  that sin(β−γ)=0 or sin2α+sin2β+sin2Υ=0.

$${If}\:\frac{{tan}\left(\alpha+\beta−\gamma\right)}{{tan}\left({a}−\beta+\gamma\right)}=\frac{{tan}\gamma}{{tan}\beta}\:{then}\:{show} \\ $$$${that}\:{sin}\left(\beta−\gamma\right)=\mathrm{0}\:{or}\:{sin}\mathrm{2}\alpha+{sin}\mathrm{2}\beta+{sin}\mathrm{2}\Upsilon=\mathrm{0}. \\ $$

Answered by myintkhaing last updated on 03/Nov/16

Commented by myintkhaing last updated on 03/Nov/16

credit Kyaw Zay Myint

$${credit}\:{Kyaw}\:{Zay}\:{Myint} \\ $$

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