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Question Number 88616 by TawaTawa1 last updated on 11/Apr/20

Commented by jagoll last updated on 28/Apr/20

$$1.x^2-4x+0=0$$$$a=1,b=-4,c=0$$

Commented by ajfour last updated on 11/Apr/20

Commented by ajfour last updated on 11/Apr/20

$$eq.oflineAByoushouldwrite$$$$first.$$$$y-9=\left(\frac{1-9}{4-0}\right)(x-0)$$$$\Rightarrow y=9-2x$$$$trapeziumareaABFOis$$$${\int }_0^4(9-2x)dx(blue+blackarea)$$$$blackarea={\int }_0^4{(x-3)}^{2}dx$$$$bluearea=(blue+black)-\left(black\right)$$$$={\int }_0^4(9-2x)dx-{\int }_0^4{(x-3)}^2$$$$=\{9x-x^2-\frac{{(x-3)}^3}{3}\}{\mid }_0^4$$$$=(36-16-\frac{1}{3})-(-\frac{{(-3)}^3}{3})$$$$=20-\frac{1}{3}-9=\frac{32}{3}.$$$$thisisthesimpleway.$$

Commented by TawaTawa1 last updated on 11/Apr/20

$$\mathrm{Wow},\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir},\mathrm{but}\mathrm{sir}\mathrm{mrW}\mathrm{got}\frac{32}{3}$$

Commented by I want to learn more last updated on 11/Apr/20

$$\mathrm{I}\mathrm{understand}\mathrm{it}\mathrm{sir}\mathrm{very}\mathrm{well}$$

Commented by TawaTawa1 last updated on 11/Apr/20

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.\mathrm{It}\mathrm{is}\mathrm{clear}.$$

Commented by jagoll last updated on 12/Apr/20

$$\mathrm{the}\mathrm{equation}\mathrm{of}\mathrm{line}$$$$\left|\begin{array}{c}09\\ 41\end{array}\right|\Rightarrow (9-1)\mathrm{x}+(4-0)\mathrm{y}=36$$$$8\mathrm{x}+4\mathrm{y}=36\Rightarrow \mathrm{y}=9-2\mathrm{x}$$$$\mathrm{the}\mathrm{parabolic}\mathrm{line}\mathrm{cut}\Rightarrow {(\mathrm{x}-3)}^2=9-2\mathrm{x}$$$${\mathrm{x}}^2-4\mathrm{x}=0,\mathrm{\Delta }=16$$$$\mathrm{area}=\frac{\mathrm{\Delta }\sqrt{\mathrm{\Delta }}}{6.{\mathrm{a}}^2}=\frac{16.4}{6.1}=\frac{32}{3}$$

Commented by TawaTawa1 last updated on 12/Apr/20

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Commented by I want to learn more last updated on 17/Apr/20

$$\mathrm{How}\mathrm{is}\mathrm{a}=1\mathrm{sir}$$

Answered by mr W last updated on 11/Apr/20

$$\frac{2}{3}\times [\frac{9+1}{2}-{(2-3)}^2]\times 4=\frac{32}{3}$$

Commented by I want to learn more last updated on 11/Apr/20

$$\mathrm{Sir},\mathrm{i}\mathrm{understand}{\int }_0^4{(\mathrm{x}-3)}^2\mathrm{dx}=\frac{28}{3}$$$$\mathrm{But}\mathrm{how}\mathrm{can}\mathrm{i}\mathrm{understand}\mathrm{the}\mathrm{other}\mathrm{part}.$$

Commented by TawaTawa1 last updated on 11/Apr/20

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir},\mathrm{i}\mathrm{also}\mathrm{have}\mathrm{the}\mathrm{same}\mathrm{question}.$$$$\mathrm{Same}\mathrm{question}{}^{\prime }\mathrm{i}\mathrm{want}\mathrm{to}\mathrm{learn}{\mathrm{asked}}^{\prime }$$

Commented by mr W last updated on 12/Apr/20

$$seeQ88758$$

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