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Question Number 88936 by naka3546 last updated on 14/Apr/20

Answered by ajfour last updated on 14/Apr/20

$$leta=\sqrt{196-c^2}from{1}^{st}$$$$b^2=2c\sqrt{196-c^2}-27from{2}^{nd}$$$$and{b}^2={(c+\sqrt{225-c^2})}^{2}from{3}^{rd}$$$$\Rightarrow$$$$2c\sqrt{196-c^2}-27={(c+\sqrt{225-c^2})}^2$$$$......$$

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