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Question Number 89007 by naka3546 last updated on 14/Apr/20

Answered by TANMAY PANACEA. last updated on 14/Apr/20

$$\frac{a^2}{b+c+d}+a$$$$\frac{a^2+ab+ac+ad}{b+c+d}$$$$\frac{a(a+b+c+d)}{b+c+d}$$$$thusgivenexpression$$$$(a+b+c+d)(\frac{a}{b+c+d}+\frac{b}{c+d+a}+\frac{c}{a+b+d}+\frac{d}{a+b+c})-(a+b+c+d)$$$$(a+b+c+d)\times 1-(a+b+c+d)$$$$=0$$

Commented by $@ty@m123 last updated on 14/Apr/20

$$Nice!!!$$

Commented by TANMAY PANACEA. last updated on 14/Apr/20

$$mosteelcomesir$$

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