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Question Number 89327 by Ar Brandon last updated on 16/Apr/20

Commented by MJS last updated on 16/Apr/20

look at qu. 89290

$$\mathrm{look}\:\mathrm{at}\:\mathrm{qu}.\:\mathrm{89290} \\ $$

Commented by Ar Brandon last updated on 17/Apr/20

OK thanks for your kind attention

$${OK}\:{thanks}\:{for}\:{your}\:{kind}\:{attention} \\ $$

Answered by jagoll last updated on 16/Apr/20

x = 17

$${x}\:=\:\mathrm{17}\: \\ $$

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