Question Number 89351 by john santu last updated on 17/Apr/20 | ||
$${prove}\:\mathrm{tan}\:\mathrm{3}^{{o}} ×\mathrm{tan}\:\mathrm{39}^{{o}} ×\mathrm{tan}\:\mathrm{89}^{{o}} \:=\:\mathrm{tan}\:\mathrm{15}^{{o}} \\ $$ | ||
Commented by MJS last updated on 17/Apr/20 | ||
$$\mathrm{it}'\mathrm{s}\:\mathrm{wrong} \\ $$ | ||
Commented by john santu last updated on 17/Apr/20 | ||
$${yes}\:{sir}?\: \\ $$ | ||
Commented by MJS last updated on 17/Apr/20 | ||
$$\mathrm{tan}\:\mathrm{3}°\:\approx.\mathrm{0524} \\ $$$$\mathrm{tan}\:\mathrm{39}°\:\approx.\mathrm{810} \\ $$$$\mathrm{tan}\:\mathrm{89}°\:\approx\mathrm{57}.\mathrm{3} \\ $$$$\mathrm{tan}\:\mathrm{15}°\:\approx.\mathrm{268} \\ $$$$\mathrm{lhs}\approx\mathrm{2}.\mathrm{43} \\ $$ | ||
Commented by john santu last updated on 17/Apr/20 | ||
$${thank}\:{you}\:{sir} \\ $$ | ||