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Question Number 89351 by john santu last updated on 17/Apr/20

prove tan 3^o ×tan 39^o ×tan 89^o  = tan 15^o

$${prove}\:\mathrm{tan}\:\mathrm{3}^{{o}} ×\mathrm{tan}\:\mathrm{39}^{{o}} ×\mathrm{tan}\:\mathrm{89}^{{o}} \:=\:\mathrm{tan}\:\mathrm{15}^{{o}} \\ $$

Commented by MJS last updated on 17/Apr/20

it′s wrong

$$\mathrm{it}'\mathrm{s}\:\mathrm{wrong} \\ $$

Commented by john santu last updated on 17/Apr/20

yes sir?

$${yes}\:{sir}?\: \\ $$

Commented by MJS last updated on 17/Apr/20

tan 3° ≈.0524  tan 39° ≈.810  tan 89° ≈57.3  tan 15° ≈.268  lhs≈2.43

$$\mathrm{tan}\:\mathrm{3}°\:\approx.\mathrm{0524} \\ $$$$\mathrm{tan}\:\mathrm{39}°\:\approx.\mathrm{810} \\ $$$$\mathrm{tan}\:\mathrm{89}°\:\approx\mathrm{57}.\mathrm{3} \\ $$$$\mathrm{tan}\:\mathrm{15}°\:\approx.\mathrm{268} \\ $$$$\mathrm{lhs}\approx\mathrm{2}.\mathrm{43} \\ $$

Commented by john santu last updated on 17/Apr/20

thank you sir

$${thank}\:{you}\:{sir} \\ $$

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