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Question Number 89660 by Mr.Panoply last updated on 18/Apr/20
$${When}\:{rolling}\:\mathrm{2}\:{dice}\:{what}\:{is}\:{the}\:{probability} \\ $$$${your}\:{not}\:{getting}\:\mathrm{2}? \\ $$
Commented by john santu last updated on 18/Apr/20
$${getting}\:\mathrm{2}?\:\mathrm{2}\:{what}? \\ $$
Commented by Mr.Panoply last updated on 18/Apr/20
$${rephrase}.\:{probability}\:{no}\:{die}\:{shows}\:{a}\:\mathrm{2}. \\ $$
Commented by mr W last updated on 18/Apr/20
$${totally}\:\mathrm{6}×\mathrm{6}=\mathrm{36}\:{possibilitie} \\ $$$${one}\:``\mathrm{2}'':\:\mathrm{2}×\mathrm{5}=\mathrm{10}\:{possibilities} \\ $$$${two}\:``\mathrm{2}'':\:\mathrm{1}\:{possibility} \\ $$$${no}\:``\mathrm{2}'':\:\mathrm{36}−\mathrm{10}−\mathrm{1}=\mathrm{25} \\ $$$$\Rightarrow{p}=\frac{\mathrm{25}}{\mathrm{36}} \\ $$
Answered by Joel578 last updated on 18/Apr/20
$$\left(\mathrm{2},\mathrm{1}\right),\:\left(\mathrm{2},\mathrm{2}\right),\:\left(\mathrm{2},\mathrm{3}\right),\:\left(\mathrm{2},\mathrm{4}\right),\:\left(\mathrm{2},\mathrm{5}\right),\:\left(\mathrm{2},\mathrm{6}\right) \\ $$$$\left(\mathrm{1},\mathrm{2}\right),\:\left(\mathrm{3},\mathrm{2}\right),\:\left(\mathrm{4},\mathrm{2}\right),\:\left(\mathrm{5},\mathrm{2}\right),\:\left(\mathrm{6},\mathrm{2}\right) \\ $$$$ \\ $$$$\mathrm{Getting}\:\mathrm{number}\:\mathrm{2}\:=\:\frac{\mathrm{11}}{\mathrm{36}} \\ $$$$\mathrm{Not}\:\mathrm{getting}\:\mathrm{number}\:\mathrm{2}\:=\:\mathrm{1}\:−\:\frac{\mathrm{11}}{\mathrm{36}}\:=\:\frac{\mathrm{25}}{\mathrm{36}} \\ $$